$17\:-\:6\:+\:4\:-\:12\:+\:3\:-\:4\:-\:9\:+\:8$
$\left(x^4+y^3\right)^3$
$\frac{dy}{dx}=\frac{x+2y}{3y-2x}$
$\left(x^2mg^2\right)^2$
$9x^2-40x+54=6x^2-22x+27$
$5abc^4-80ab$
$\frac{1-1}{\sqrt{31-2-1}}$
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