$y'=\left(\frac{2x}{y-x}\right)$
$4\sin^2x=-2\sin x+6$
$a^2-2a-3\:\frac{a}{3}$
$17\cdot69$
$\frac{x^2+2}{x+3}>x$
$\left(-2\right)^3-3\left(-2\right)^2+4\left(-2\right)-2$
$\left(3x^4-5x\right)^2$
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