$\:\frac{\cos\left(-x\right)}{\tan\left(-x\right)}-\sin\:x=-\csc\:x\:$
$\left(2x+4\right):5+2$
$\frac{3x^2+16x+21}{x+4}$
$2+\{-[-\left(7+8\right)+\left(4-3\right)]-2\}$
$\int2x\left(x^2+9\right)^5\:dx$
$\:-24\:-\:\left(-18\right)\:$
$\left|3-11\right|-\left|14\right|$
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