$\lim_{x\to0}\:\frac{1-cos3x}{x}$
$\lim_{x\to2}\left(\frac{6x^2-15x+6}{6x^2-12x+5}\right)$
$wv-4w-5v+20$
$2x+5\ge4x+6$
$\frac{1+\frac{1}{\cos\:\left(y\right)}}{\frac{\sin\:\left(y\right)}{\cos\:\left(y\right)}+\sin\:\left(y\right)}=\frac{1}{\sin\left(y\right)}$
$y=y-y^3$
$+39+89$
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