$\lim_{x\to\infty}\left(\frac{\left(-2\right)^x\left(x\right)}{4+x}\right)$
$2yx+7y+4y+6y^2$
$\frac{15x^7}{5x^4}$
$\frac{s^2+3s+3}{\left(s+1\right)\left(s+3\right)}$
$2^2\cdot y^2$
$x^2-4x+2y=0$
$\lim_{x\to0}\left(\frac{5-5x\sqrt{1+x}}{x\sqrt{1+x}}\right)$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!