$2\sin^4x+\sin^2x-1$
$\lim_{x\to-5}\left(\frac{-8\left|x\right|+40}{2x+10}\right)$
$\frac{-5}{0}$
$\:\lim_{x\to\:3}\:\frac{x^2-4}{11-2x}$
$\left(3w+7\right)\left(3w+4\right)$
$4-4x^2+4x^4$
$3z-1=\frac{z\left(3z+1\right)}{2}$
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