$8\left(4c+1\right)+10c$
$\left(\frac{2x}{x+1}\right)^2$
$2x^4-16x$
$-9\:+\:-19\:+\:-6\:+\:1\:+\:50$
$\left(-2\right).\left(5-7\right)-\left(-3\right).\:\left(8-6\right)$
$\left(2a+\sqrt{2}^2\right)$
$\int\frac{\left(a^x+b^x\right)^2}{a^xb^x}dx$
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