$\left(2xy-5y^2\right)^2$
$\left(3a-2\right)=\frac{a+25}{a+1}$
$\frac{\left(\infty\:+1\right)}{\infty\left(\infty+2\right)\left(\infty^2-2\infty+5\right)}$
$\lim_{x\to5}\left(\frac{5-x}{x}\right)$
$5+4.\:5$
$\int\cos\left(\frac{1}{4}x\right)dx$
$1-2\cdot5$
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