$2\left(x-3\right)+5>5-x$
$-6xy-8+5x^2+6xy-9$
$\left(s+8\right)\left(s-9\right)$
$\frac{b^2}{b}$
$\left(2\right)^3-3\left(2\right)^2+4\left(2\right)-2$
$\left(-4\right)-\left(-18\right)$
$5.6\sqrt[4]{6}+0.08\sqrt[4]{6}+5.25\sqrt[4]{6}$
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