$x\:y\:dy=\left(y+1\right)\left(1-x\right)dx$
$3x^3+7x^2-4$
$f\left(x\right)\:=\left(2x-3\right)^5\:\left(x^2+\:4x\right)^6$
$3m^4n\:+\:2m^4n^5+\:3m^4n\:+\:5m^4n^5$
$-\:\left(-8\:+\:2\right)\:\cdot\left(-2\:-1\right)$
$y'-\frac{4y}{t}=t^2$
$\frac{x^3+6x^3-12x-9}{x+3}$
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