$\left(a^3-6\right)\left(a^3+6\right)$
$\frac{d^2y}{dx^2}\left(x^{-1}-\frac{1}{5}x^6+\frac{1}{4}x^5-x^3\right)$
$3b^2\cdot4a^4$
$\frac{2x+8}{x-2}=-1$
$\:-\:\left[\:3\:-\:7\left(8\:-\:6\right)\right]\:-\:\left(7\:-\:1\right)\:+\:4\left[\:8\:-\:\left(4\:-\:3\right)\:-\:4\right]\:+\:7$
$\lim_{y\to3}\left(\frac{y^2+y-12}{x^2}\right)$
$x-\sqrt{2}>0$
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