$y'''-2y''+2y'=0$
$x^5+\frac{1}{x^5}$
$\left(\frac{x}{6}\right)=\left(\frac{x}{13}\right)$
$x-1=-20x^2$
$3\sqrt{-27x^4y^{13}}$
$\left(3x-12\right)^2$
$\frac{a^2-49b^2}{a+7b}$
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