$x^2x+28$
$\int x^2\left(2x\ln\left(x\right)+2x\right)dx$
$28\cdot\left(24-16\right)\cdot2$
$\lim\:_{x\to\:0}\left(\frac{\sqrt[3]{\left(cos\left(x-1\right)\right)^2}}{tan\left(x\right)}\right)$
$x^2+16x+64=36$
$3x+10=2x+40$
$75-5\left(2.6\right)$
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