$\left(9x+3\right)\left(9x+8\right)$
$3y^2\frac{dy}{dx}=8x$
$\frac{960}{16}$
$\int x\left(x^2y\right)dy$
$\left(1-\tan\left(a\right)\right)^2$
$-3\cdot36$
$\frac{\left(x^2+x+2\right)^5}{x-1}$
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