$\int\left(\frac{sec\:x}{1+tan\:x}\right)^2dx$
$\:\left(4m+8v\right)$
$\left(x^3+\frac{1}{27}\right)^3$
$x^2+8x+8$
$\frac{4}{5}\left(20x-10\right)$
$\left(6ax^2y\right)\left(3a^5xy\right)$
$35m^2\left(n^3-2m\right)$
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