$1-3x\le4$
$18+x^2-6x=0$
$\frac{4x^3-36}{2x-6}$
$1348.17+215.139+5.12+28.9$
$\left(2m-3n\right)^5$
$\left(2x+1\right)^2-\left(2x-1\right)^2-8y$
$\int\:3cosh^2\left(x-3\right)sinh\left(x-3\right)dx$
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