$\left(2x-y\right)\left(z+4y\right)$
$\frac{900}{180}$
$60x^2-13x-24$
$23+\frac{10}{2\:}+5\cdot3+4-5\cdot2-8+4$
$4x+2y=10$
$4\left(x\:-3\right)\:-\:3\left(4\:-\:2x\right)$
$\frac{y\sqrt{3}-2}{2\sqrt{3}+2}$
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