$2b^2-6b+4$
$\frac{\left(6.5\cdot10^{-12}\right)\left(5\cdot10^{10}\right)}{\left(1.3\cdot10^6\right)}$
$2t^2+1+4t$
$\frac{1}{4}b^2-25$
$t\cdot\frac{dx}{dt}=x$
$\log_{10}\left(x^2+10\right)=\log_{10}\left(3x-12\right)$
$x^5-7x^3-x^2$
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