$x-4x$
$-3x=48$
$-7+4^2$
$_{\left(-8\right)}-\left(17\right)-\left(-34\right)-\left(_{-99}\right)$
$a^{4}-b^{4}=\left(a-b\right)\left(a^{3}+a^{2}b+ab^{2}+b^{3}\right)$
$1+2\cdot5$
$\sqrt[3]{2.7}$
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