$\int\frac{\sqrt{x^2+6}}{x^4}dx$
$\left(\frac{1}{4}m^3\right)^3$
$\frac{x^3+3x-2}{x+2}$
$x^2-3xy+y^2-2y^2+3xy-x^2.x^2+3xy-y^2$
$n+5\cdot n+7$
$-6x^4\cdot\left(-4x\right)$
$185\cdot12$
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