$b2-6b+4=0$
$6-\left(3x-2i\right)^2$
$\int\tan^{2}\left(x\right)\cos^{3}\left(x\right)dx$
$25\cdot\sin\left(x\right)-12=0$
$5\left(x-\frac{3}{2}\right)\le3x+1$
$\frac{18x^3-18x^2-18x+17}{6x+6}$
$432\:+223$
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