$-4\cdot\left(7-8\right)$
$\lim_{x\to\infty}\left(\frac{x^4-16}{x^3-8}\right)$
$\sqrt[3]{125m^9n^6}$
$x^2+6x\le0$
$\log\left(x+6\right)-\frac{1}{2}\log\left(2x-3\right)=2-\log\left(25\right)$
$1.1063-22.8472$
$\left(20t^2+t\right)^2-22\left(20t^2+t\right)+21$
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