$\lim_{x\to\infty}\left(\frac{ln\left(x^8-5\right)}{ln\left(x\right)cos\left(\frac{1}{x}\right)}\right)$

$a3\:+\:8$

$\int\frac{4\left(x+1\right)}{\left(2x+1\right)}dx$

$f\left(x\right)=\left(4x^3+x^2\right)$

$-2x<5-4x$

$\sin^2x\sec^2x=\frac{1}{\cot^2x}$

$\frac{4^4}{4^{-8}}\cdot4^{-14}$