$\left(3zy^3-4x^2\right)\:^3$
$\lim_{x\to\infty}\:\:\frac{\left(\left(2+x\right)x\right)}{\left(1+x\right)^{\left(4\right)}}$
$-3x^2ym+7x-ymx^2+16x$
$\frac{\left(x^2+x-1\right)}{x+2x+x}$
$r^2+r+5=0$
$15x^2-55x-20$
$\frac{dy}{dx}+\frac{2xy}{1+x^2}=\frac{1}{\left(1+x^2\right)^2}$
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