$\int\frac{x^2}{\left(x+1\right)\left(x-2\right)\left(x^2+1\right)}dx$
$\left(2x^2-3\right)\left(2x^2+5\right)$
$12x^2y^2\:-15xy^2\:-\:6x^2$
$3\left(2x\:+\:5\right)\left(x\:-\:4\right)$
$4.572\cdot100$
$x-21=6$
$\frac{dv}{dt}=\frac{3v\sqrt{1+t^2}}{t}$
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