$cos2a+cosa+1=0$
$\frac{4x^2+3x+2}{x-3}$
$2x^2+2x=1$
$\left(9x+8\right)\left(x^2+2x+9\right)$
$\left(x-4\right)\left(x+2\right)\ge0$
$-7-4-11-4-2-7-4-5-8$
$\frac{d}{dx}\:\:2arctan\:\left(\frac{2}{w^2}\right)$
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