$\frac{dy}{dx}=\frac{3x^2+4x+4}{2y-4}$
$\int\frac{e^{4x}}{1+5\:e^{4x}}dx$
$y'=\frac{2}{x^2}\left(e^{2x}-xy\right);y\left(1\right)=2e^2$
$y'\:+2xy\:=\:xy^2$
$a^2+2a+3a+a^2$
$\frac{dy}{dx}+1=8x-y$
$xy1$
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