$5=v+2$
$\frac{64y^{12}-2^6}{2y^2+z}$
$1-sec^2x=-tan^2x$
$\frac{dy}{dx}=\frac{-\left(x^3+y^3\right)}{3xy^2}$
$y'-y=te^t$
$\frac{1-cos2x}{2sinx}=sinx$
$m^2-4m=m.\left(m-4\right)$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!