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$\left(2x^3y^2\right)\left(5x^3yz^2\right)$

Final answer to the exercise

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Other solved exercises

$\left(x^2-3\right)\left(x^2-6x+9\right)$

$\frac{2z+6x}{n}$

$x^{\frac{1}{3}}=\sqrt[3]{x}$

$\sqrt{9x^{16}y^6}$

$x^2-4x=5$

$9+y+y+3$

$5\ln\left(6x+9\right)+20=5$
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