$\left(5ab-6\right)^2$
$\int\frac{x^3}{x^4-3}dx$
$\left(k-2\right)\left(k+4\right)=0$
$3-2>-6$
$\left(6-11\right)\left(8-13\right)$
$5-3\cdot4$
$\left(y^2-5y-1\right)^2+\left(y-4\right)^2$
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