$12:2+-8\cdot\left(-3\right)$
$\int\left(3x^3-3x\right)^4\left(3x^{2\:}\:-1\right)dx$
$9a^2-12a^4+9a+8-8a+a^4$
$\left(x^2+8\right);\:x=2;\:y=x^3-3$
$\left(\ln x\right)^{2}=\ln x$
$arccos\:\left(x^2-2x+2\right)=0$
$\left(9a^2+4b^2-4c^2\right)^2$
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