$\lim_{x\to\infty}\left(\sqrt{1+\frac{3}{4}.\frac{1}{x}}\right)$
$\int be^{bt+2}dt$
$\left(4c^2\cdot2c^2\cdot c\right)^3$
$\left(a-c\right)^2;\:a=-1;\:b=2;\:c=-\frac{1}{2}$
$\left(2b^3+5\right)\left(2b^3-5\right)$
$-x^2-2x+6=0$
$\left(-675\right)+\left(-148\right)+\left(216\right)$
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