$4x-3\ge8$
$tanx\:+\:tan^3x$
$7y+8-3y-1+y$
$-13-26-55+120+48$
$\left(x^2+1\right)\left(x+2\right)$
$\int\frac{x^2+3x+7}{x+1}dx$
$15.75+4.00+2.25$
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