$\int\frac{\left(24x^7\right)}{\sqrt{8-x^8}}dx$
$4\left(-13\right)+20$
$\frac{1}{\left(-6+6x\right)}$
$8\left(c+2\right)$
$\frac{6x^3-7x^2+2}{3x+1}$
$-x+3\:=\:-\left(x-3\right)$
$\frac{2}{x-1}=\frac{5}{x+2}$
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