$8x\ge5000$
$1+\frac{1}{4}-\frac{169}{4}$
$\frac{x^{3\:}-12x+16}{x-2}$
$25r^4-144$
$\frac{120}{4}$
$\left(-3\right)^2-4\left(1\right)\left(-3\right)$
$\lim_{x\to\infty}\left(\frac{x^3-2x^2-7x+21}{x^6+1}\right)$
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