$\frac{y}{x}=u$
$4x^2+26x+40$
$+5x+3x-6x-3$
$y'+\left(\frac{2\cdot y}{x}\right)=x^3$
$\frac{d}{dx}\frac{4x-9}{3x+4}$
$\cos^{2}\left(3x\right)-\sin^{2}\left(3x\right)$
$\int5\sec\left(3x^2-4\right)xdx$
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