$y'+3y\:=12\:,\:y\left(0\right)=6$
$\left(18x^3y^2z^5\right)-\left(6x^3yz^2\right)$
$\frac{3x^4-2x^3+4x-8}{x+3}$
$\int\left(4x-9x^2+7x\:+\:3\right)e^{-x}dx$
$12a-5a-3a+8a+9a$
$\ln\left(x\left(x^2+2\right)\right)$
$\frac{2x}{\sqrt{30}}$
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