$y=\left(2x-5\right)^4\left(8x^2-5\right)^{-3}$
$sec3x=2$
$\lim_{x\to1}\left(\frac{x^3-2x^2+4x-3}{4x^2-5x+1}\right)$
$\left(a^2+5b\right)\left(a^4-5a^2+25b^2\right)$
$\frac{dy}{dx}=y^2-6y+13$
$\left(3f^2-4g^3\right)^2$
$-2x^2-5xy,x=-1,y=2$
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