$\frac{12x}{x+3}>x+3$
$3\infty+1$
$-6x^2+4x+2x+7x^2-7x^2$
$3x+4y=-5$
$\sin a-12=-11.5$
$\left(5a^{5\:}-3d^{4\:}\right)\left(5a^{5\:}+3d^{4\:}\right)$
$7c^3-10c^4+10c^4+14c^7-9c^4-12c^3$
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