$\frac{2x^2+2x+3}{2}$
$\frac{d}{dx}\left(\frac{400x}{\ln\left(2x+7\right)}\right)$
$-3\left(2x-10\right)+8\left(x+6\right)$
$a-2b+2c=2$
$1-2cos^2\:a+\cos^{4\:}a=\sin^4\:a$
$3y+2-6y-8$
$\frac{2x^3-3x+2}{x+3}$
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