$t\cdot y'\:+\:2\cdot y\:=\:4\cdot t^2,\:y\left(1\right)\:=\:2.$
$\left(2x^2+3x-4\right)$
$j\left(t\right)=3900\left(5\right)^{3t+2}$
$s^2\:t^4\:x\:s^7\:t^3$
$x^2+\frac{5}{6}x$
$\frac{x^2-3x+3}{x+1}$
$\frac{x^3+4x^2+x+6}{x+1}$
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