$f\left(x\right)=\left(3x\right)^{ln3x}$
$a^2+ab^2$
$\left(\frac{2}{3}a\:+\frac{2}{5}b\right)^2$
$\left(-28\right)-\left(-12\right)$
$x+2=\left(10-x\right)^2$
$\lim_{x\to0}\left(\frac{\sin}{x+3x^2}\right)$
$\lim_{x\to1}\:\frac{1}{\left|x-2\right|}$
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