$5x^{4}x+3y+5x^{4}+3$
$( r ^ { 4 } ) ^ { 6 }$
$4p=-12$
$\left(a^3b^2-2\right)^3$
$\int_0^32x^2+2x+3\:-\left(x^2-4x+3\right)dx$
$\int\left(\frac{x}{\sqrt{x-11}}\right)dx$
$\int\frac{\left(x^5+x-1\right)}{x\left(x^3+1\right)}dx$
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