$\sqrt{9x^2-18+5}$
$\left(\frac{x}{x+2}\right)+\left(\frac{5}{x-2}\right)$
$500\le100x-2x^2-120$
$13\:-\:\left(-4\right)\:$
$x^{2\:}+12x=18$
$\left(5a+2b^3\right)\left(5a-7b^3\right)$
$\frac{x-3}{3}-2<4$
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