$\int x^2\left(x^3-3\right)^8dx$

$\frac{3xy}{dx}=\frac{2y^2}{dy}$

$\left(\:3m^3\:-\:8n^2\:\right)\left(\:9m^6\:+\:24m^3n^2\:+\:64n^4\right)$

$\left(1-6y^5\right)\frac{dy}{dx}=x\cos\left(x\right)$

$\int cost^2\:2tdt$

$86\cdot26$

$\left(3\right)\left(3m^2\right)\left(2n^2\right)$