$\lim_{x\to-\infty}\left(\frac{\sqrt{x^2+4}-2x}{x}\right)$
$45x^2+60x+20$
$35\:-\:\left(-19\right)\:\:$
$\frac{\left(s^3+5s^2+9s+7\right)}{\left(s+1\right)\left(s+2\right)}$
$tan^2x=2secx+2$
$4z^3-\:5z^2=\:0\:\:$
$3x^2+12x+15$
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