$\left(-13\right)\cdot\left(-4d\right)$
$\frac{4+\cos\left(x\right)\tan\left(x\right)\csc\left(x\right)}{\sec\left(x\right)}$
$2x^2-10$
$5^3\cdot10^3$
$144a^6b^8-81b^{12}$
$4-2x+4x=-8$
$-7\cdot7\cdot7\cdot7\cdot7\cdot7$
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