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Exercise

$\left(2m+3n^2\right)^3$

Step-by-step Solution

1

Apply the formula: $\left(a+b\right)^3$$=a^3+3a^2b+3ab^2+b^3$, where $a=2m$, $b=3n^2$ and $a+b=2m+3n^2$

$\left(2m\right)^3+9\left(2m\right)^2n^2+6m\left(3n^2\right)^2+\left(3n^2\right)^3$

Final answer to the exercise

$\left(2m\right)^3+9\left(2m\right)^2n^2+6m\left(3n^2\right)^2+\left(3n^2\right)^3$

Try other ways to solve this exercise

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