$y^2\frac{dy}{dx}=3$
$\int x\left(3x+4\right)^{\frac{1}{3}}dx$
$\left(6-x\right)\left(x+4\right)$
$cosx=sinx$
$csc\left(x\right)cot\left(x\right)=\frac{1+cot^2\left(x\right)}{sec\left(x\right)}$
$13a+22b-81c-12x+4-\left(10a-20b+35c-2x+1\right)$
$-7x+4+3x$
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