$\left(\sqrt{12}z^3+21y+\frac{1}{8}x^2\right)^2$
$-3\:\cdot\:5+4\:\cdot\:-2$
$\int\left(\left(8x+1\right)^2\left(8\right)\right)dx$
$4xy+12xy+20abxy-30abxy$
$256x^2-64x+4$
$\frac{dv}{ds}=\frac{s+1}{sv+s}$
$x^3-6x^2+16x$
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